Suppose 15 drops of cyanic acid, HONO (K. = 3.5 * 10), solution had been titrated with 41 drops of 0.22 M NaOH. Complete

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Suppose 15 Drops Of Cyanic Acid Hono K 3 5 10 Solution Had Been Titrated With 41 Drops Of 0 22 M Naoh Complete 1 (39.2 KiB) Viewed 34 times

Suppose 15 drops of cyanic acid, HONO (K. = 3.5 * 10), solution had been titrated with 41 drops of 0.22 M NaOH. Complete the table. (0.60 M 0.015 M. 1.84, 2.406) Calculation Rounded Answer (with units) Calculation Setup (with unrounded answer) is dropS XHUFIONIDE HANDPSXD 22m 03 MONDEO 1. Concentration of cyanic acid solution COM b. Hydrogen ion concen tration in cyanic acid solution 001019 0.015 c. pH of cyanic acid solution PHED - 1090 0.0145 a. Percent ionization of 2006 x 100 = 2.412 cyanic acid solution 2.42 6. Compare the calculated percent ionizations for Part A and Part B. 7. The concentration of the diluted acetic acid solution in Part B can be calculated by the dilution for mula (MV, = M,V) instead of by titration. Use this formula to calculate the molarity of the diluted acetic acid solution 8. How does the calculated experimental concentration of the diluted solution from Part B compare to the concentration calculated in Question 7? Which do you think is more accurate, titration or dilution formula? Explain. Instructors Initials Lab 14