TT P.-Paloin Throat Flow VP -A/A3) 2:23 B. 1930 pts. Aventuri meter has air (p = 0.075 lb/ft,u=0.018 CP) flowing through
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
TT P.-Paloin Throat Flow VP -A/A3) 2:23 B. 1930 pts. Aventuri meter has air (p = 0.075 lb/ft,u=0.018 CP) flowing through
TT P.-Paloin Throat Flow VP -A/A3) 2:23 B. 1930 pts. Aventuri meter has air (p = 0.075 lb/ft,u=0.018 CP) flowing through it. The attached manometer currently displays a pressure drop of 10% of water. The diameters at the upstream location and at the throat are 3.5 in and 1.0 in, respectively. A, ID2 D = 0,= V2 A2 A, A. What is the volumetric flow rate of air in ft/min? Assume C = 1.0.615 pts. ✓ CVQIP-P) Pelt A3 V.P 3 CuaTORST SGM d = 3.5in = 0.29aft 0-0751bm|ft (-(1999 "d2= 10 = 0·0833ft 381 - 2 = 11)/2 101bf ft? 1 - 1.0in? 2 =4.0ftis inz 10.075 lbml 3.sin? Q Q = 17 x (6,08332 x 2 = 1.61 ft3/min B. Using the plot below, determine the correct C, value to use. 1.00 Manometer 7/10 pts. 0.99 V2cm Rex 8 = 4,9280.0833 you PElmin ft 0.58 T 2012 0.97 М. 0.96 0.018 cP 1498.7639 095 X R-2541.263 D2 -0.2852 0.29 Di 094 104 2 5 6 8 10 3 4 5 6 8 10% R-VD,DIA [Cv=0.647 Cu= 5/5pts. C. What is the volumetric flow rate of air in ft/min using the answer from part b? al 6 ( 22 S 2 (P.-P2) 0.64(6) 60.083332162 =T.DE { 1.032 Ft?lmin Downstream of the threat of the venturi meter, the diameter increases back to the original Pair (1 - ATAR
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!