SOUDALMI Brief Background of Marble Game or Guseulchigi The Korean drama, Squid game showed one of the ways to play a Ma

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SOUDALMI Brief Background of Marble Game or Guseulchigi The Korean drama, Squid game showed one of the ways to play a Ma

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Soudalmi Brief Background Of Marble Game Or Guseulchigi The Korean Drama Squid Game Showed One Of The Ways To Play A Ma 1
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SOUDALMI Brief Background of Marble Game or Guseulchigi The Korean drama, Squid game showed one of the ways to play a Marble Game which is called Holjjang. Each player was given a pouch containing ten marbles and chose their partner to play with. One person grabs marbles, and the other person guesses whether the number of marbles is odd or even. They bet the number of marbles before playing, and give or take the marbles according to the results of the guessing. The only regulation of the Marble Game was that one player from each couple had to win by collecting 20 marbles.

The standard deviation of a discrete random variable X is written o. It is the square root of the variance. The standard deviation is computed as: = [x2P(x)] - u2 Example 3: In Seungri High School fair, two games are conducted using six-sided die. For game A, you will win 20.00 if the result of rolling the die is "1","8. the result is "2". Otherwise, you will lose W10.00. For game B, you will win 24.00 if the result is "1" or "2". Otherwise, you lose W15.00. The tables shown in the next page display the probability distribution for winning or losing the money for both games. What is the variance of the each game? W8 - W10 Game A Amount of money, W20 x P(x) Game B Amount of money, 24 - #15 X P(x) 2 For Game A: Steps 1. Find the mean of the probability distribution using the formula, y = [xP(x)] (1+ )+(-10) (1) Solution H = (20) + (8) 10 -20 = -6 u= = -2 --- [c20): () +c+() +(-10ºC)-(-29 = [(400) () + (64) () + 100)(3) -4 (200+ O2 02 2. Substitute the given in the formula, o2 = [x2P(x)] – 3. Simplify values that have an exponent. 4. Multiply the results obtained in Step 3 and its corresponding probabilities. 5. Add the values obtained Step 4. O2 = 144 - 4 6. Subtract the square mean from the result obtained in Step 5. o2 = 140 7. To get the standard deviation, take the square root of the o=V140 0 = 11.83 32 2001 + 3 4 GE (x2P(x)] – ki? variance. 14

Dr Game B: -Il = -2 = -4 | Steps Solution 1. Find the mean of the + = (24) () +(-15) (8) probability distribution using u= 8+ (-10) the formula, u = [xP(x)] 2. Substitute the given in the o? = [(24)2 (2) +(-15); ()]-(-2)2 formula, o2 = {[x2P(x)]- 12 3. Simplify values that have an *= (576) () +(225) (3) -- exponent. 4. Multiply the results obtained in 02 = [192 +150] -4 Step 3 and its corresponding probabilities. 5. Add the values obtained Step 4.02 = 342 – 4 6. Subtract the square mean from the result obtained in Step 5. 7. To get the standard deviation, ix?P(x)] – 222 take the square root of the variance. 02 = 338 0= o = 338 o = 18.38 a To interpret the results, the standard deviations of game A and game B are 11.83 and 18.38, respectively. Since game A has a smaller standard deviation, this means that there are more data that is closer to the mean. When game A is played many times, notice a smaller spread or variation of winning or losing than playing game B.
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