Show that for any r, n > 1, n! Σ =r". ni+n2+...+nr=n, ni 20 ni!n2! ...Nr! The summation above runs over all (n1, n2 ...,

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answerhappygod
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Show that for any r, n > 1, n! Σ =r". ni+n2+...+nr=n, ni 20 ni!n2! ...Nr! The summation above runs over all (n1, n2 ...,

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Show that for any r, n > 1, n! Σ =r". ni+n2+...+nr=n, ni 20 ni!n2! ...Nr! The summation above runs over all (n1, n2 ..., Nr) satisfying n1 + N2 + ... + ny = n, ni > 0.
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