Nodal Equation 100°C 8 q 10 8500 7 5 3 14 2 1 h=18 w/mok Too=10°c K=11 w/mik AX=5 cm 100c yo 85°C 5 1=18 h=18 21 To 10

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answerhappygod
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Nodal Equation 100°C 8 q 10 8500 7 5 3 14 2 1 h=18 w/mok Too=10°c K=11 w/mik AX=5 cm 100c yo 85°C 5 1=18 h=18 21 To 10

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Nodal Equation 100 C 8 Q 10 8500 7 5 3 14 2 1 H 18 W Mok Too 10 C K 11 W Mik Ax 5 Cm 100c Yo 85 C 5 1 18 H 18 21 To 10 1
Nodal Equation 100 C 8 Q 10 8500 7 5 3 14 2 1 H 18 W Mok Too 10 C K 11 W Mik Ax 5 Cm 100c Yo 85 C 5 1 18 H 18 21 To 10 1 (34.11 KiB) Viewed 28 times
Nodal Equation 100 C 8 Q 10 8500 7 5 3 14 2 1 H 18 W Mok Too 10 C K 11 W Mik Ax 5 Cm 100c Yo 85 C 5 1 18 H 18 21 To 10 2
Nodal Equation 100 C 8 Q 10 8500 7 5 3 14 2 1 H 18 W Mok Too 10 C K 11 W Mik Ax 5 Cm 100c Yo 85 C 5 1 18 H 18 21 To 10 2 (37.13 KiB) Viewed 28 times
Nodal Equation 100 C 8 Q 10 8500 7 5 3 14 2 1 H 18 W Mok Too 10 C K 11 W Mik Ax 5 Cm 100c Yo 85 C 5 1 18 H 18 21 To 10 3
Nodal Equation 100 C 8 Q 10 8500 7 5 3 14 2 1 H 18 W Mok Too 10 C K 11 W Mik Ax 5 Cm 100c Yo 85 C 5 1 18 H 18 21 To 10 3 (33.65 KiB) Viewed 28 times
Nodal Equation 100 C 8 Q 10 8500 7 5 3 14 2 1 H 18 W Mok Too 10 C K 11 W Mik Ax 5 Cm 100c Yo 85 C 5 1 18 H 18 21 To 10 4
Nodal Equation 100 C 8 Q 10 8500 7 5 3 14 2 1 H 18 W Mok Too 10 C K 11 W Mik Ax 5 Cm 100c Yo 85 C 5 1 18 H 18 21 To 10 4 (33.65 KiB) Viewed 28 times
Nodal Equation 100 C 8 Q 10 8500 7 5 3 14 2 1 H 18 W Mok Too 10 C K 11 W Mik Ax 5 Cm 100c Yo 85 C 5 1 18 H 18 21 To 10 5
Nodal Equation 100 C 8 Q 10 8500 7 5 3 14 2 1 H 18 W Mok Too 10 C K 11 W Mik Ax 5 Cm 100c Yo 85 C 5 1 18 H 18 21 To 10 5 (42.23 KiB) Viewed 28 times
Nodal Equation 100°C 8 q 10 8500 7 5 3 14 2 1 h=18 w/mok Too=10°c K=11 w/mik AX=5 cm
100c yo 85°C 5 1=18 h=18 21 To 10 h=18 W/m.k なにわ Ax=5cm K= 11 11 W/mok
100°C 8 9 110 a 8500 7 5 3 14 J Too h=18 w/mok Too = 10°c K=11 w/mik AX=5cm
Table 32 Summary of Nodi Formator Finderne Coons Dundee Dement Volume) Physical situation (a) Interior node Nadal for equal incremeno Creation in form for Get Seldal Barat OT. +++T...- .. Tao Tarot Tant Tout Tante 1. ---- - Larseas (b) Convection boundary node - m. 0 = " Art. 01...+ T.... +T) - (***+ 2)... T+T+T12 BiT. T. m. 2 - B har -1 ܫܠ ܬ (c) Exterior comer with convection boundary - m 1, . 0 - 2 T. + (-+ Ine-3-2 (+)2 + But T. 1 + Bi Η ΔΣ Bi Ay m-1 (d) Interior corner with convection boundary ܫܠ 0 - 2 - 1 + 21-12 + 2a.se + Tuska + In-1 = 2(3+ **) *. - +1 Bi T. +...++ (T... + -12 T- 3 + Bi * Δε Bi * -1., 1. m! andrey
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