3. For w = 150 kN/m, a = 50 mm, and a pin diameter of 20 mm, the average shear stress in the pin is best given by X. 23.
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
3. For w = 150 kN/m, a = 50 mm, and a pin diameter of 20 mm, the average shear stress in the pin is best given by X. 23.
3. For w = 150 kN/m, a = 50 mm, and a pin diameter of 20 mm, the average shear stress in the pin is best given by X. 23.9 MPa b. 5.97 MPa 11.9 MPa d. 47.7 MPa r-w 150 A T202 A: 314,15 لے 2 pin ponts «43 ПРА 150 T202= 1250=11.9
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!