- 3 Determine The Maximum Bending Stress Created In The Structure Below From The Applied Moment M Of 175 Kn M 300 Mm 20 1 (19.16 KiB) Viewed 24 times
- 3 Determine The Maximum Bending Stress Created In The Structure Below From The Applied Moment M Of 175 Kn M 300 Mm 20 2 (54.78 KiB) Viewed 24 times
Formula and Materials sheet: Factor of Safety = U.T.S./6 O =P/AG = E€ o = Mc/ 8=PL/(AE) 8= a *L* AT T = Tc/) T = P/A T = GY = TL/(JG) 8 = PL/(AE) Pr = $y* c/ J = 3.14*c*/2 (Solid Bar) J = 3.14*(c29-C1")/2 (Hollow Bar) I = bh/12 (Rectangle) 1-3.14*r*/4 (Circle) 1x = le+Ad? ΥΣΑ = ΣyA Power Force *Velocity=Work/time Key: o=Stress, t=Shear Stress, P=Force, A=Area, M=Moment, I=Moment of Inertia, E=Young's Modulus, E=strain T=Torque, Ty=Elastic Torque, J=Polar Moment of Inertia, G=Modulus of Rigidity, Y-Shear Strain, =Angle of Twist, L=Length, 8=deformation, b=breadth, h-height, d, y, Y, C=distance or radius, pr-radius of elastic core, a=coefficient of expansion, U.T.S.= Ultimate Tensile Strength Material Youngs Modulus (GPa) 200 Yield Stress (MPa) Ultimate Tensile Strength (MPa) Modulus Coefficient of Rigidity of Expansion (GPa) (10*/C) 200 12 Steel Aluminium 70 30 23 250 (Normal) 150 (Shear) 95 (Normal) 55 (Shear) 220 (Normal) 150 (Shear) 12 400 (Normal and Shear) 110 (Normal) 70 (Shear) 70 (Normal and Shear) Copper 120 40 17 Concrete 25