6 A Concrete Slab 15ft Long 12ft Wide And 10 In Thick Is Subjected To A Total Temperature Differential At Of 20 1 (54.35 KiB) Viewed 26 times
6 A Concrete Slab 15ft Long 12ft Wide And 10 In Thick Is Subjected To A Total Temperature Differential At Of 20 2 (25.56 KiB) Viewed 26 times
6. A concrete slab (15ft long, 12ft wide, and 10 in thick) is subjected to a total temperature differential (AT) of -20°F (at day time). Assume k=200 pci and a=5x10 in./in./°F. The radius of relative stiffness () is 36.1" as shown below. Lx= 15ft - 180in. Oy Ly=12ft = 144 in. Ox Gy E - 4x10"psi y 0.15 B O h-10 in 0 LI 0 1.0 09 αΔΤΕ. (C+vC) 2(1 - v!) αΔΤΕ 2(1-v) C, +C.) where a=thermal expansion coefficient, Es elastic modulus of concrete, v=Poisson's ratio, and C, and C - correction factors. 08 07 0.6 C 0.5 0.4 0.3 L-free length or width of a {-radius of relative stiffness Ctres coefficient is either directions 1/4 . 0.2 0.1 :- - - [128 ER 12(1-vP) 114 4x10 • 10 = 36.1" 12+ (1 -0.15)* 200 LE 0 9 10 11 12 13 14 1 2 3 4 5 6 7 8 LE (a) Calculate the maximum curling stresses in X- and y-directions (Grand ay) at the interior (A) and at the edge (B) of the slab. (20 points)
(b) Calculate the edge stress in the concrete pavement due to a circular tire loading (a=10") with a uniform tire pressure of 70 psi applied at point B. (10 points) (e) Calculate the combined stresses (in x-direction only) at the edge (point B) due to temperature and wheel load at day time. (10 points)
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