QUESTION 35 Horizontal positions of two benchmarks are given. Coordinates of the benchmark A are: Na = 500.00 m and EA =

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QUESTION 35 Horizontal positions of two benchmarks are given. Coordinates of the benchmark A are: Na = 500.00 m and EA =

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Question 35 Horizontal Positions Of Two Benchmarks Are Given Coordinates Of The Benchmark A Are Na 500 00 M And Ea 1
Question 35 Horizontal Positions Of Two Benchmarks Are Given Coordinates Of The Benchmark A Are Na 500 00 M And Ea 1 (75.1 KiB) Viewed 41 times
QUESTION 35 Horizontal positions of two benchmarks are given. Coordinates of the benchmark A are: Na = 500.00 m and EA = 500.00 m. Coordinates of the benchmark B are: NB = 853.55 m and E8 = 853.55 m. The horizontal coordinates of a new point P were measured by applying the angle-angle intersection. The angle BPAB at the point A is 44º. The angle BABP at the point B is 45° (see the survey scheme). P a BP 1 1 1 1 BABP B I PAB d AP БА
Firstly, compute the geodetic azimuths (bearings) CAP and CBP from measured angles BPAB and BABP. Then apply the bearing-bearing intersection method to compute the horizontal coordinates Np and Ep of a point P according to the following expressions: = Eg-E A + NA tan a ap -Ng tan dgp N, (tan Cap-tan dgp Ng-NA+EA cota AP-E, cot Asp EQ.18 Ep = (cot & Ap-cot App Finally compute the standard deviations ONp and OEp of horizontal coordinates Np and Ep of a point P. The geodetic azimuth (bearing) CAP was determined with the accuracy characterized by the standard deviation of OAP = £7”. The geodetic azimuth (bearing) ABP was determined with the accuracy characterized by the standard deviation of OaBp=+6”. The horizontal coordinates Np and Ep of a new point and their standard deviations are: O Np = 853.55=0.02 m and Ep = 506.17+0.01 m O Np = 853.55+0.02 m and Ep = 506.17+0.02 m O Np = 853.55€0.01 m and Ep = 506.17€0.02 m O Np = 853.55+0.01 m and Ep = 506.17+0.01 m
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