(7%) Problem 5: Penny is adjusting the position of a stand up piano of mass m₂ = 210 kg in her living room. The piano is

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7 Problem 5 Penny Is Adjusting The Position Of A Stand Up Piano Of Mass M 210 Kg In Her Living Room The Piano Is 1 (168.26 KiB) Viewed 36 times

(7%) Problem 5: Penny is adjusting the position of a stand up piano of mass m₂ = 210 kg in her living room. The piano is lp = 1.35 m in length. The piano is currently at an angle of 0p = 48 degrees to the wall. Penny wants to rotate the piano across the carpeted floor so that it is flat up against the wall. To move the piano, Penny pushes on it at the point furthest from the wall. This piano does not have wheels, so you can assume that the friction between the piano and the rug acts at the center of mass of the piano. Randomized Variables mp = 210 kg p=1.35 m 0p = 48 degrees FOtheexpertta.c A 33% Part (a) Write an expression for the minimum magnitude of the force F, in N Penny needs to exert on the piano to get it moving. Assume the corner of the piano on the wall doesn't slide and the static friction between the rug and the piano is μg. A 33% Part (b) The coefficient of kinetic friction between the carpet and the piano is μ = 0.27. Once the piano starts moving, calculate the torque Tp N-m that Penny needs to apply to keep moving the piano at a constant angular velocity. ▷ A 33% Part (c) Calculate the amount of work Wp in J Penny does on the piano as she rotates it. Wp = Grade Summary Deductions Potential 10 sin() cos() cotan() asin() tan() π ( acos() E sinh() 7 8 9 HOME 4 5 6 1 2 Submissions Attempts remainin (5% per attempt) detailed view atan() acotan() 3 cosh() tanh() cotanh() 0 END Degrees Radians ^^^ 1 - + Jol 0 p ܢܢܢܢܢܢܠ