Hey I'm a little confused, if you could explain the answer Id greatly appreciate it
You wish to cool a 2.07 kg block of tin initially at 84.0°C to a temperature of 49.0°C by placing it in a container of kerosene Initially at 32,0°C. Determine the volume (in L) of the liquid needed in order to accomplish this task without boiling. The density and specific heat of kerosene are respectively 820 kg/m³ and 2,010 J/(kg "C), and the specific heat of tin is 21.8 J/(kg - °C).
You wish to cool a 2.07 kg block of tin initially at 84.0°C to a temperature of 49.0°C by placing it in a container of k
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You wish to cool a 2.07 kg block of tin initially at 84.0°C to a temperature of 49.0°C by placing it in a container of k
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