Iodine undergoes a decay process as follows: ¹241 → Te + e+ + v. Rewrite this reaction, filling in the missing numbers.

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answerhappygod
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Iodine undergoes a decay process as follows: ¹241 → Te + e+ + v. Rewrite this reaction, filling in the missing numbers.

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Iodine Undergoes A Decay Process As Follows 241 Te E V Rewrite This Reaction Filling In The Missing Numbers 1
Iodine Undergoes A Decay Process As Follows 241 Te E V Rewrite This Reaction Filling In The Missing Numbers 1 (36.73 KiB) Viewed 27 times
Iodine undergoes a decay process as follows: ¹241 → Te + e+ + v. Rewrite this reaction, filling in the missing numbers. Help chemPad XX Greek What sort of decay is this? O inverse beta decay O alpha decay O beta decay
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