1. The schematic for Young's double-slit experiment is shown in the following figure. In the experiment, the distance from the double-slit to the screen is much larger than the width of the interference pattern on the screen. Let L = 1.50 m and d = 0.10 mm. The slit system is illuminated with monochromatic light of wavelength 500 nm. .../10 Viewing screen
a) Calculate the position of the third-order maximum fringes on the screen as measured from position O. (2 marks) = b) Calculate the phase difference between the two wave fronts arriving at P when y 5.00 mm (2 marks) c) With the help of equations, describe how the interference pattern on the screen will change under the following situations (such changes include the position and intensity of the fringe, the separation between neighboring fringes etc.) (6 marks) i. The screen is moved away from the two slits. ii. The monochromatic wavelength from the point source is increased. iii. The distance "d" between the two slits is increased. iv. Two light sources are used instead and the light from different sources is forced to pass through different slits. V. A thin glass plate is inserted behind the slit S2. vi. An ideal linear polarizer is inserted behind each slit. The transmission axes of the polarizers are perpendicular to each other.
1. The schematic for Young's double-slit experiment is shown in the following figure. In the experiment, the distance fr
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
1. The schematic for Young's double-slit experiment is shown in the following figure. In the experiment, the distance fr
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!