An object is moving in a circular motion law: s(t)=2t^3=3t^2+4. In t=2s, the module of its total acceleration is a=40m/

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answerhappygod
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An object is moving in a circular motion law: s(t)=2t^3=3t^2+4. In t=2s, the module of its total acceleration is a=40m/

Post by answerhappygod »

An object is moving in a circular motion law:
s(t)=2t^3=3t^2+4. In t=2s, the module of its total acceleration is
a=40m/s^2
Compute the Radius R of the circle. Compute the module of the
acceleration in t=1s.
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