full question here:
Add any remaining curved arrows to show the two propagation steps that form the observed products (Note: Br₂ is produced by the reaction of HBr with NBS, and is present in small concentrations). Do NOT add curved arrows to convert the first resonance structure into the second resonance structure. CH₂ H₂C CH₂ H₂C H₂C CH₂ H₂C HG H₂C CH₂ Edit Drawing H₂C H₂C CH₂ CH₂
For each of the products shown in the following reaction, propose a mechanism that explains its formation: Br Br-H Part 1 Correct. This mechanism begins with an initiation step to form a Br radical. A propagation step (Hatom abstraction) generates an allylic radical intermediate that is resonance-stabilized. The delocalized radical can be attacked by Bra (Br atom abstraction) at either of two locations to generate the two observed products. Note: Br₂ is produced by the reaction of HBr with NBS, and is present in small concentrations. Identify the most likely sequence of curved arrows in the mechanism to form the second product shown. X= NBS hv +
Part 2 Correct. In the initiation step, the N-Br bond is broken to generate a bromine radical. Draw single-barbed (fish-hook) arrows for the initiation step of this process, and modify the given structure to draw the resulting two radicals. & Hint ➜
Add any remaining curved arrows to show the two propagation steps that form the observed products (Note: Br₂ is produced
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Add any remaining curved arrows to show the two propagation steps that form the observed products (Note: Br₂ is produced
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