- Exercise Hints Getting Started I M Stuck If The Two Lenses In The Figure Are Separated By 11 6 Cm Locate The Final Im 1 (20.58 KiB) Viewed 31 times
- Exercise Hints Getting Started I M Stuck If The Two Lenses In The Figure Are Separated By 11 6 Cm Locate The Final Im 2 (25.49 KiB) Viewed 31 times
- Exercise Hints Getting Started I M Stuck If The Two Lenses In The Figure Are Separated By 11 6 Cm Locate The Final Im 3 (25.49 KiB) Viewed 31 times
- Exercise Hints Getting Started I M Stuck If The Two Lenses In The Figure Are Separated By 11 6 Cm Locate The Final Im 4 (36.77 KiB) Viewed 31 times
PRACTICE IT Use the worked example above to help you solve this problem. Two converging lenses are placed d₂ = 23.2 cm apart, as shown in figure a, with an object d₁ = 34.8 cm in front of lens 1 on the left. (a) If lens 1 has a focal length of f₁ = 11.6 cm, locate the image formed by this lens and determine its magnification. 9= 17.4 cm M= -0.5 = 23.2 cm, locate the image (b) If lens 2 on the right has a focal length of f₂5 formed and find the total magnification of the system. 9= -7.734 cm M = -0.67 ****************
(A) Locate the image and determine the magnification of lens 1. See the ray diagram, figure b. Apply the thin lens equation to lens 1. 1 1 1 + 30.0 cmq 10.0 cm Solve for q, which is positive and hence to the right of the first lens. q=+15.0 cm Compute the magnification of lens 1. 15.0 cm M₁₂ 9 ==== -=-0.500 Р 30.0 cm (B) Locate the final image and find the total magnification. The image formed by lens 1 becomes the object for lens 2. Compute the object distance for lens 2. p=20.0 cm 15.0 cm = 5.00 cm Once again apply the thin lens equation to lens 2 to locate the final image. 1 1 1 + 5.00 cm q 20.0 cm 9 = -6.67 cm Calculate the magnification of lens 2. 9 ==== M₂ (-6.67) 5.00 cm = +1.33 Р Multiply the two magnifications to get the overall magnification of the system. M = M₁M₂ = (-0.500)(1.33) = -0.665