Question 11 10 pts Many different interest groups-such as the lumber industry, ecologists, and foresters-benefit from be

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Question 11 10 Pts Many Different Interest Groups Such As The Lumber Industry Ecologists And Foresters Benefit From Be 1 (49.79 KiB) Viewed 36 times

Question 11 10 Pts Many Different Interest Groups Such As The Lumber Industry Ecologists And Foresters Benefit From Be 2 (16.39 KiB) Viewed 36 times

Question 11 10 pts Many different interest groups-such as the lumber industry, ecologists, and foresters-benefit from being able to predict the volume (in cubic feet) of a tree just by knowing its diameter (in inches). Let's use a data set (Shortleaf 3.xlsx) of n-70 shortleaf pines to learn not only about the relationship between the diameter and volume of shortleaf pines, but also about the benefits of simultaneously transforming both the response variable and the explanatory variable. NOTE: Copy and paste the wordings (highlighted is yellow) into the section below as is appropriate. Use only the highlighted wordings. Do not add any extra space or symbol when copying and pasting into the text box. a) Make a scatterplot showing the diameter vs. volume. Describe the association. R2 (round answer to 4 decimal places. Please use a zero (0) before the decimal point] low high not linear- linear Although the R² is quite the fitted line plot suggests that the relationship between tree volume and tree diameter is b) Make a scatterplot showing the logarithm (og10) of diameter vs. volume. Describe the association. diameter volume changed - did not change Transforming only the values the non-linearity at all. c) Make a scatterplot showing the logarithm (log 10) of diameter vs. logarithm (log 10) of volume. Describe the association. Let's see if transforming both the diameter and volume values does it for us. Wow! The fitted line plot should give us hope! R³- (round answer to 4 decimal places. Please use a zero (0) before the decimal point non-linear and weak linear and strong linear and weak The relationship between the log 10 of the diameter and the log 10 of the volume looks The regression equation is: log 10(diameter) = xlog 10(volume) (round answer to decimal places!
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