Question 7. For some t > 1, let X be a random variable taking the values 0 and t, with probabilities: 1 1 P(X = 0) 1 & P

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

Question 7. For some t > 1, let X be a random variable taking the values 0 and t, with probabilities: 1 1 P(X = 0) 1 & P

Post by answerhappygod »

Question 7 For Some T 1 Let X Be A Random Variable Taking The Values 0 And T With Probabilities 1 1 P X 0 1 P 1
Question 7 For Some T 1 Let X Be A Random Variable Taking The Values 0 And T With Probabilities 1 1 P X 0 1 P 1 (40.92 KiB) Viewed 26 times
Question 7. For some t > 1, let X be a random variable taking the values 0 and t, with probabilities: 1 1 P(X = 0) 1 & P(X = t) t t □ Var(X) = = t □ Var(X) = 1/t E[X] = 1 □ E[X] = t Var(X) = t - 1 ☐ E[X]=t² □ E[X] =1/t None of these answers are correct □ Var(X) = t² - - =
Question 8. ♣ We still keep the notations of Question 7. For every a in R, define the probability I(t) := P(|X − 1| > a). Chebyshev's inequality provides an upper bound of It). Besides, when one can com- pute exactly It), we can compute the difference between the upper bound obtained by Chebyshev's inequality and I). We call it the Chebyshev gap for X, at a and for t. We denote it e(t) (a). = Hence, it is easy to see that, if t = 10 and a = 8, then (¹0) 1/10 and that Chebyshev's inequality provides 9/64, as an upper bound of I(10). Hence, the Chebyshev gap for X, at a = 8 and for t = 10 is equal to 9/64 - 1/10 = 9/80. In other words, one can write: (10) 9 80 ≈ 0.04. □ C ☐ (¹0) = 7/12. ☐ (¹0) = 1/25. 10) 3 □ C = □ (¹0) (5) = ☐ (¹0) = 12/7. 10 10 None of these answers are correct ₂(10) 13 50 Question 9. We still keep the notations of Question 7 to 8. One can affirm that: (10) None of these answers are correct ☐ = 0. □ (¹0) = 2/9. 7 ☐ (10) = 1/10. ¹10 (10) 10* 9 3 2 □ (10(10): = □ (10) 100 100 25 Question 10. We still keep the notations of Question 7 to 9. More generally, for any t in (1, ∞), one can affirm that: 1 □ I(t) = 0, Va> t. ☐ I(t) = 0, Va<t. □ I(t) = Va> t > 1. = Va > t > 1. t2³ □ (10) = 1/3. □ (¹0) (10) = None of these answers are correct ☐ ¹0) = 1/10. (10) (10)
Question 11. We still keep the notations of Question 7 to 9. More generally, for any t in (1, ∞), one can affirm using Chebychev's inequality, that: ■ [(¹) < 22, Va>t≥1. □ I(¹) < 7, Vt > a. ☐ I(t) 1, Va>t. a t None of these answers are correct ☐ (¹) < Va> t. a "One might have to use the inequality t − 1 ≤ a, valid for all a > t. Question 12. We still keep the notations of Question 7 to 11. One wonders here if one can find a gap smaller than a certain number. One can affirm that: None of these answers are correct □ One can find a gap smaller than 10-2. □ One can find a gap smaller than 10-P, for all p in N*. One can find a gap smaller than 10-³. ☐ There are some p in N*, for which one can not find a gap smaller than 10¯º, for all p in N* One can not find a gap smaller than 10-7. Question 13. (Optional) We still keep the notations of Question 7 to 12. One can affirm that: None of these answers are correct ☐ One can not improve Chebychev Inequality, in general. □ One can improve Chebychev Inequality, in general.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply