Question 1 For the series parallel circuit shown below on Figure 1. Calculate R₂ = 60 R₁ = 2.50 R₁ = 40 R₁-212 -200 V a)
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Question 1 For the series parallel circuit shown below on Figure 1. Calculate R₂ = 60 R₁ = 2.50 R₁ = 40 R₁-212 -200 V a)
Question 1 For the series parallel circuit shown below on Figure 1. Calculate R₂ = 60 R₁ = 2.50 R₁ = 40 R₁-212 -200 V a) The supply current. b) The current flowing through each resistor? c) The p.d across each resistor? Question 2 1₁ R₁=150 R₂=1002 12 Figure 2 Calculate a) The value of Rx such that the power dissipated in the circuit is 2.5kW. b) The current flowing in each for resistors (18) (7) Question 3 Explain where can current divider rule be applied and where can Voltage divider rule can be applied? Figure 1. 250 V R3=38 2 Rx (6) (7) (8)
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