Please answer (iv) and (v) only
4. Consider the CFG S→SS | XaXaX | A X→bX A (i) Prove that X can generate any b*. (ii) Prove that XaXaX can generate any b*ab*ab*. (iii) Prove that S can generate (b*ab*ab*)*. (iv) Prove that the language of this CFG is the set of all words in (a + b)* with an even number of a's with the following exception: We consider the word ▲ to have an even number of a's, as do all words with no a's, but of the words with no a's only A can be generated. (v) Show how the difficulty in part (iv) can be alleviated by adding the production S→XS
4. Consider the CFG S→SS | XaXaX | A X→bX A (i) Prove that X can generate any b*. (ii) Prove that XaXaX can generate any
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4. Consider the CFG S→SS | XaXaX | A X→bX A (i) Prove that X can generate any b*. (ii) Prove that XaXaX can generate any
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