the node numbers are denoted by circles and member numbers are denoted by boxes please insert boundary conditions in MAT

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answerhappygod
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the node numbers are denoted by circles and member numbers are denoted by boxes please insert boundary conditions in MAT

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the node numbers are denoted by circles and member numbers are denoted by boxes
The Node Numbers Are Denoted By Circles And Member Numbers Are Denoted By Boxes Please Insert Boundary Conditions In Mat 1
The Node Numbers Are Denoted By Circles And Member Numbers Are Denoted By Boxes Please Insert Boundary Conditions In Mat 1 (32.53 KiB) Viewed 31 times
The Node Numbers Are Denoted By Circles And Member Numbers Are Denoted By Boxes Please Insert Boundary Conditions In Mat 2
The Node Numbers Are Denoted By Circles And Member Numbers Are Denoted By Boxes Please Insert Boundary Conditions In Mat 2 (27.32 KiB) Viewed 31 times
The Node Numbers Are Denoted By Circles And Member Numbers Are Denoted By Boxes Please Insert Boundary Conditions In Mat 3
The Node Numbers Are Denoted By Circles And Member Numbers Are Denoted By Boxes Please Insert Boundary Conditions In Mat 3 (30.63 KiB) Viewed 31 times
The Node Numbers Are Denoted By Circles And Member Numbers Are Denoted By Boxes Please Insert Boundary Conditions In Mat 4
The Node Numbers Are Denoted By Circles And Member Numbers Are Denoted By Boxes Please Insert Boundary Conditions In Mat 4 (34.91 KiB) Viewed 31 times
please insert boundary conditions in MATLAB usung directions provided.
L tw I L 22 P P P Figure 2: Idealized Truss Geometry The half weight of each passenger car is P = 2 k. The member spacing is L = 20 ft. The cross section of each truss member is constant and shown in Figure 2 above. Each truss member is made of A992 steel, which has E = 29,000 ksi. 柯 L L L
DOF numbering: For each node, there are two DOFs: displacement in x and y. The DOF number for each node is listed below. Note that this numbering system is different from what we usually do in class (Unknown DOF first then Known DOF). We assign the DOF from lower node to higher node for simplicity of the assembly process. Node DOF (x displacement) DOF (y displacement) 1 1 2 2 3 4 5 6 7 8 10 12 14 16 3 45678 9 11 13 15
Node information: For each member, the near nodes and far nodes are summarized in the following table. Member Near Node Far Node 1 1 2 2 2 3 3 3 4 4 4 5 5 1 6 6 2 6 7 3 6 8 3 7 9 3 8 10 8 11 8 12 7 13. 8 23 45 4 5 6 7
From line 45 to 47, you need to put the boundary conditions (known dofs). The displacement is denoted by u (16X1 vector). Similar to the load vector, input your DOF number in the bracket and enter the known displacement value. There are 3 values you need to input. Note that you need to follow closely to the numbering system in section 1. u( )= u( )= u( )= After defining your member stiffness matrix, applied load vector and known dofs, you can press run and the code will give you the nodal force and displacement.
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