- How Many Grams Of Br Are Needed To Form 66 6 G Of Albrz 2 Al S 3 Br 1 2 Albr3 S Step 1 Show The Strategy For S 1 (59.77 KiB) Viewed 40 times
How many grams of Br₂ are needed to form 66.6 g of AlBrz? 2 Al(s) + 3 Br₂(1)→ 2 AlBr3(s) Step 1: Show the strategy for s
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How many grams of Br₂ are needed to form 66.6 g of AlBrz? 2 Al(s) + 3 Br₂(1)→ 2 AlBr3(s) Step 1: Show the strategy for s
How many grams of Br₂ are needed to form 66.6 g of AlBrz? 2 Al(s) + 3 Br₂(1)→ 2 AlBr3(s) Step 1: Show the strategy for solving this problem. grams AlBr₂ Answer Bank grams Br₂ moles Br₂ moles Al grams AlBr₂ moles AlBr3 grams Al Step 2: Show the conversions required to solve this problem and calculate the grams of Br₂. 66.6 g AlBr3 X X X = g Br₂ 2 moles Al 3 moles Br, 2 moles AlBr3 grams of Br₂: 26.98 g Al 159.80 g Br₂ 266.68 g AlBr3 Answer Bank 1 mole Al 1 mole Br₂ 1 mole AlBr3 grams Br₂ g Br₂
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