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tell me the weight of isoamyl acetate and how to obtain mole.
wa H₂ OH (10.6g) ethanoic acid CH3 + Ho Mon но CM3 (23.0g) isoamyl alwhol 52504 H3C O CH3 Ho Mens (x g) isoamyl acetate
wa H₂ OH (10.6g) ethanoic acid CH3 + Ho Mon но CM3 (23.0g) isoamyl alwhol 52504 H3C O CH3 Ho Mens (x g) isoamyl acetate
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answerhappygod
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wa H₂ OH (10.6g) ethanoic acid CH3 + Ho Mon но CM3 (23.0g) isoamyl alwhol 52504 H3C O CH3 Ho Mens (x g) isoamyl acetate
How do you get the theoretical yield from this equation? Please
tell me the weight of isoamyl acetate and how to obtain mole.
wa H₂ OH (10.6g) ethanoic acid CH3 + Ho Mon но CM3 (23.0g) isoamyl alwhol 52504 H3C O CH3 Ho Mens (x g) isoamyl acetate
tell me the weight of isoamyl acetate and how to obtain mole.
wa H₂ OH (10.6g) ethanoic acid CH3 + Ho Mon но CM3 (23.0g) isoamyl alwhol 52504 H3C O CH3 Ho Mens (x g) isoamyl acetate
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