Please Answer Number2 1 (35.76 KiB) Viewed 40 times
Please Answer Number2 2 (26.68 KiB) Viewed 40 times
By determining the volume of nitrogen gas adsorbed by a material as a function of p/p. at 293 K is obtained as follow. p/pv (m³/kg) 0.05 0.068 0.10 0.075 0.15 0.083 0.20 0.090 0.25 0.095 0.30 0.103 0.40 0.121 0.50 0.138 1. Estimate the volume of nitrogen adsorbed over 1 kg of this material when a monolayer is formed. 1 c-1 (p 1 = (Note: (²) + v[p/po-1] vmc VmC 1 P then plot graph between and to obtain slope and intercept and then the v[p/p-1] po monolayer adsorbed gas quantity (Vm) can be calculated.)
2. Determine the total and specific surface area and specific surface area of this materials (Given: The cross sectional area occupied by one nitrogen molecule is 16 x 10-20m².) (Note: Total surface area is the number of moles of gas adsorbed multiply by the cross-section of each adsorbed gas molecule. VmNAS V where S,: total surface area, N₁: Avogadro's number, s: the cross sectional area of absorbed gas molecule And specific surface area SBET where m: mass of sample
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