I need to derive the equation in the red box in very clear steps and in step by step.
Scattering of a linearly polarized beam with an arbitrary direction of polarization 2 &² = E3²x + E04 220 Cos Egx E Egy cos Zo 20 2.80* ६ Eo,y E = Ex + ₁ Ex E In a linearly polarized beam incident along the z axis, the electric field amplitude in any particular direction and its x and y components obey E = E + E and, in the beam forward scattered at zero scattering angle along the z axis, &² = {²+ & At a point at distance R from the electron, e² 1 &=- -E mc² R and similarly for its x and y components, where the negative sign is present because & and its x and y components are antiparallel to E, and its x and y components due to the phase flip that occurs on scattering,. For consistency with notation to be introduced later, the scattering angle between the incident beam and a scattered beam is denoted 20 where is the angle that the incident and scattered beams each make with the bisector of the scattering angle. Then with respect to the forward scattered beam at zero scattering angle, the beam scattered at an angle 20 to a point at a distance R from the electron has amplitude components & and & cos 20, and the resultant scattered amplitude for the given, particular polarization direction is 0.y Eost
I need to derive the equation in the red box in very clear steps and in step by step.
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answerhappygod
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I need to derive the equation in the red box in very clear steps and in step by step.
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