- 3 3 1 Show That The Energy Of A Circular Orbit In The Isochrone Potential 2 47 Is E Gm 2a Where A B R L 1 (18.41 KiB) Viewed 53 times
3.3 [1] Show that the energy of a circular orbit in the isochrone potential (2.47) is E = -GM/(2a), where a = √b²+ r². L
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3.3 [1] Show that the energy of a circular orbit in the isochrone potential (2.47) is E = -GM/(2a), where a = √b²+ r². L
3.3 [1] Show that the energy of a circular orbit in the isochrone potential (2.47) is E = -GM/(2a), where a = √b²+ r². Let the angular momentum of this orbit be Le(E). Show that Lc = √GMb (x-¹/2 - ¹/²), 2Eb where x = (3.327) GM
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