2. Prove: For every integer n ≥ 1, CY f 1² +2²+ 3² +...+ n² = n (n + 1) (2n + 1) 6
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2. Prove: For every integer n ≥ 1, CY f 1² +2²+ 3² +...+ n² = n (n + 1) (2n + 1) 6
2. Prove: For every integer n ≥ 1, CY f 1² +2²+ 3² +...+ n² = n (n + 1) (2n + 1) 6
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