4. S 5. f 6. dxxx¹/5x(lnx) (x+1)(x+3) dzxe¹/= (z+1)(z²+1)(z²+9)(z+3) de 3/2+cos (0) ; 7. 1.th on the circle |z| = 2 daxe
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4. S 5. f 6. dxxx¹/5x(lnx) (x+1)(x+3) dzxe¹/= (z+1)(z²+1)(z²+9)(z+3) de 3/2+cos (0) ; 7. 1.th on the circle |z| = 2 daxe
4. S 5. f 6. dxxx¹/5x(lnx) (x+1)(x+3) dzxe¹/= (z+1)(z²+1)(z²+9)(z+3) de 3/2+cos (0) ; 7. 1.th on the circle |z| = 2 daxeikz 1+² with k>0 [4
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