5) P-substitution. Solve the following ODES. dy dy (d)² + ( |-6=0 dx dx a. Solution: (-3x+C₁) (2x + C₂ ) = 0 d²y dv b. +

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5 P Substitution Solve The Following Odes Dy Dy D 6 0 Dx Dx A Solution 3x C 2x C 0 D Y Dv B 1 (33.64 KiB) Viewed 28 times

5) P-substitution. Solve the following ODES. dy dy (d)² + ( |-6=0 dx dx a. Solution: (-3x+C₁) (2x + C₂ ) = 0 d²y dv b. + = 0 dx² dx Solutions ’: y =|Cx+C, Y₂ = C3 7 Here, there are two questions that you should be able to answer. i) How do you decide on the sign in front of the square root in the first solution, why not minus? ii) Where does the second solution come from? y