A block a force 1168 N is shown on an incline of 29. A force 1127 N is applied to it horizontally. 1168N s =0.35 k=0.25

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A block a force 1168 N is shown on an incline of 29. A force 1127 N is applied to it horizontally. 1168N s =0.35 k=0.25

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A Block A Force 1168 N Is Shown On An Incline Of 29 A Force 1127 N Is Applied To It Horizontally 1168n S 0 35 K 0 25 1
A Block A Force 1168 N Is Shown On An Incline Of 29 A Force 1127 N Is Applied To It Horizontally 1168n S 0 35 K 0 25 1 (83.6 KiB) Viewed 39 times
A block a force 1168 N is shown on an incline of 29. A force 1127 N is applied to it horizontally. 1168N s =0.35 k=0.25 29 a) Determine if the block is in equilibrium. The block is in equilibrium b) Find the magnitude and direction of the frictional force on the block. The magnitude of the force is The normal force is N and it is normal to the ramp c) If the block is in motion, determine whether it's moving up or down the ramp. The maximum friction force is Fax N. not in motion 1127N N and it is down the ramp
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