This question has several parts that must be completed sequentially. If you skip a part of the question, you will not re

[answerhappygod]

This Question Has Several Parts That Must Be Completed Sequentially If You Skip A Part Of The Question You Will Not Re 1 (103.64 KiB) Viewed 43 times

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise The index of refraction for violet light in silica flint glass is 1.66, and that for red light is 1.62. What is the angular spread of visible light passing through a prism of apex angle 60.0° if the angle of incidence is 50.5°? See figure below. Deviation of red light Visible light R G Angular spread B v Screen Step 1 The prism produces a rainbow, separating the colors of a narrow beam of incoming white light. Even if the angular dispersion is small, we will see a clear spectrum far away from the prism. Step 2 We will trace the rays of violet light and red light through the prism, finding the direction angle of each ray as it exits the prism. Subtracting these angles will give us the angular width of the spectrum between them. Step 3 We label the angles of incidence and refraction at the surface of entry with e, and 8 2, respectively, and the internal angle and external angle to the exit surface with 83 and 84, respectively, as shown in the diagram below. The apex angle o = 60° is the angle between the surfaces of entry and exit. The ray in the glass forms a triangle with these surfaces in which the interior angles must add to up 180°. Thus, (90° - 2) + 0 + (90° -63) = 180°, so we have 03 = 0 - 2 ф Jon
Step 1 The prism produces a rainbow, separating the colors of a narrow beam of incoming white light. Even if the angular dispersion is small, we will see a clear spectrum far away from the prism. Step 2 We will trace the rays of violet light and red light through the prism, finding the direction angle of each ray as it exits the prism. Subtracting these angles will give us the angular width of the spectrum between them. Step 3 We label the angles of incidence and refraction at the surface of entry with e, and 8 2, respectively, and the internal angle and external angle to the exit surface with 83 and 84, respectively, as shown in the diagram below. The apex angle o = 60° is the angle between the surfaces of entry and exit. The ray in the glass forms a triangle with these surfaces in which the interior angles must add to up 180°. Thus, (90° - 2) + 0 + (90° -63) = 180°, so we have 03 = 0 - 2 DAN hos A general form of Snell's law for light going through a prism where n is the index of refraction of the prism material is given by the following. sin @ = n sin ez Solving for @ for each wavelength of light, we have the following. (Express all calculated values to four significant figures.) sin 180 X (2) violet = sin Your response differs from the correct answer by more than 100%. X 1.66 Your response differs from the correct answer by more than 100%. 40180 4.0 180 x sin 180 x (2) red = sin( your response differs from the correct answer by more than 100%. 1.62 Your response differs from the correct answer by more than 100%. Submit Skip (you cannot come back)