25 Points A Conducting Rod Of Length L 10 Cm Is Free To Slide On Two Parallel Conducting Bars As Shown In The Fi 1 (76.02 KiB) Viewed 41 times
25 Points A Conducting Rod Of Length L 10 Cm Is Free To Slide On Two Parallel Conducting Bars As Shown In The Fi 2 (23.89 KiB) Viewed 41 times
- [25 points) A conducting rod of length L = 10 (cm) is free to slide on two parallel conducting bars as shown in the figure. A resistor R = 5 [Q] is connected across the ends of the bar to form a loop. The rod and the bars are located in a region that has a magnetic field of magnitude B = 2.5 [T] directed into the page. An external agent pulls the rod with a constant speed v = 0.2 [m/s] in the direction shown in the figure. THE BELOW PARTS ARE INDEPENDANT. a 4 1. [5 points) The magnetic flux throughout the loop is: - 2. [5 points) Calculate the value of the induced EMF in the loop. JEMF = [V] dx = vdt X Х х Х Х Х X X во Xin X IR. 88 х х х 3. [5 points) X X X X X Х Considering the value of the EMF is (EMF) = 0.15 [V], calculate the value of the induced current in the loop. I = (A) 4. [5 points) Considering the value of the EMF is EMF] = 0.15 [V] and that of the current is I = 0.01 (A), calculate the value of the power dissipated in the resistor.
P = [W] 5. [5 points] Considering the value of the current is I = 0.01 (A), calculate the magnitude of the applied force that is needed to move the rod with this constant speed. F = [N]
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