For the right hand side, we need to figure out qene. Since we are calculating the Electric field in between the two cyli

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For The Right Hand Side We Need To Figure Out Qene Since We Are Calculating The Electric Field In Between The Two Cyli 1 (79.79 KiB) Viewed 33 times

For the right hand side, we need to figure out qene. Since we are calculating the Electric field in between the two cylinders, the only enclosed charge will be from the inner cylinder. Which of the following represents the correct expression for this enclosed charge: σα(4nalyptune. ₁(2nal) Gafna²) Other: iv. Normally, we would solve for the electric field from here, but there is a little quirk of solving for the capacitance of an infinite object. You can't solve for the capacitance since it is infinite (i.e. C = but an infinite cylinder has an infinite amount of charge. So instead we solve for the capacitance per unit length). For reasons you will see shortly, simply use Qe for the total charge enclosed where Qa is the total charge on the inner cylinder inside of our Gaussian surface. Now solve for the electric field: E = VoHage Finally, solve for the potential difference between the two cylinders. AV=√4- Vo C. Given your answer to the previous part, we can solve for the capacitance per unit length, =Based upon your difference in potential, what is the capacitance of an infinite cylinder with two radii a and b?