2 points Gravity Force Vectors Three buildings (each with a mass of m) are arranged in an equilateral triangle with the

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2 points Gravity Force Vectors Three buildings (each with a mass of m) are arranged in an equilateral triangle with the

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2 Points Gravity Force Vectors Three Buildings Each With A Mass Of M Are Arranged In An Equilateral Triangle With The 1
2 Points Gravity Force Vectors Three Buildings Each With A Mass Of M Are Arranged In An Equilateral Triangle With The 1 (27.52 KiB) Viewed 30 times
2 points Gravity Force Vectors Three buildings (each with a mass of m) are arranged in an equilateral triangle with the centers of the buildings separated by a distance d. The magnitude of the net gravity force on each building (due to the other buildings) in Fhet m F d 13.8m N 2.34x 10 kg Type your answer 2 points m x 10 kg d 14. 6m Fort 5.48N Type your answer Solutions This solution uses a coordinate system with 2 of the masses on the x-axis. One gravity force vector points in the direction. The other force vector makes a 60° angle with the x-axis Use trigonometry to calculate the components of the net force Fut -F+F cos 60 Forty-F sin 60 Calculate the magnitude using Pythagorean Theorem FutF+F cos 60°) (F sin 60%) Factor Fout of the square root: F. = F (1 + cos 60°) + (sin 60°) Plugin F Gm Free (1+cos 60°)2 + (sin 60°)
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