Q" be the total four-momentum of the inital state. Then we can stick on an additional overall four-momentum conserving 8

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Q Be The Total Four Momentum Of The Inital State Then We Can Stick On An Additional Overall Four Momentum Conserving 8 1 (11.28 KiB) Viewed 28 times

Q Be The Total Four Momentum Of The Inital State Then We Can Stick On An Additional Overall Four Momentum Conserving 8 2 (18.24 KiB) Viewed 28 times

Q Be The Total Four Momentum Of The Inital State Then We Can Stick On An Additional Overall Four Momentum Conserving 8 3 (12.13 KiB) Viewed 28 times

Q" be the total four-momentum of the inital state. Then we can stick on an additional overall four-momentum conserving 8-function: N TI | 1,= |(27)"5" (2-Č») ] <*p (21)ālp? – m?). dl *) (3) =1
Now assume that you are in the center of momentum frame for the initial state. This means that the total four-momentum is simply Q = (Ecm,0,0,0) (7) Use the total four-momentum conserving 8-function to integrate over the three-momentum of the second final state particle, đp2. It should be easy to find that dp = (8) 2E (28)8(Ecm - E - Ey) | allz - S 26,263
Pass to spherical coordinates for pi. Note that the energies are independent of the angular coordinates. They do, however, depend on the magnitude pıl = |P2) = p. Integrate over the remaining 8-function to show that d112 - IL/ 6. 1 P 16n? Есм do d cos 0