explain only part b, why tmax at 1 and tmin at 3.
because of the engine cycle, and always like this
The cycle in question for reference: [4pts) for parts (b) and (c) together P (b) Compute the ratio Tmax/TMIN of the highest and the lowest temperature the gas achieves as it goes around the cycle. 1-2 and 3-4: adiabatic 2-3: constant pressure 4-1: constant volume (c) Compute work done by the gas during segment 1-2. Let P3 = P2, P1 = 4P2 and P4 = 3P2. 2 Assume that there are N molecules of gas, each with f quadratic degrees of freedom. During adiabatic compression, PVN and VTS/2 are constant, v = (f + 2)/f. You may use P, and V2 in your answer, but not the other pressures or volumes. Question 5. Solution: (b) 1/7 P2 TMAX TMIN 3 Ti T3 PAY PV1 P3V3 = 4P2 V4 =4 =4 P2 V3 P.MY = 4.3-1/93 4 3f/(f+2) 3P2
The cycle in question for reference: [4pts) for parts (b) and (c) together P (b) Compute the ratio Tmax/TMIN of the high
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The cycle in question for reference: [4pts) for parts (b) and (c) together P (b) Compute the ratio Tmax/TMIN of the high
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