1. Consider the percentage difference between the tow and the tow for the first two parts of the laboratory when known f
Posted: Fri Apr 29, 2022 11:45 am
1. Consider the percentage difference between the tow and the tow for the first two parts of the laboratory when known forces are balanced. A difference of 0.5% or less is excellent, a difference of 1.0% or less is good, and a difference of 2% or less is acceptable. Based on these criteria, describe your results for the first two parts of the laboratory and defend your statement. but not guarantee 2. Using the same criteria as in Question 1 for the percentage differences, describe your results for the determination of mass of the meter stick in Part 3 of the laboratory and for the determination of the lever arm of the mass me in Part 4 of the laboratory
LABORATORY REPORT Meter Stick Data Table mass of inter 94.9 8= 0.0949 kg center balance m = 49.7 cm 0.497 m balang in molt inu % Difference Data and Calculations Table 1 Mass Position my=100 g 0.100 kg x = 10.0 cm -0.100 m m2 = 200 g =0.200 kg x2 =-11cm=0.69m opposte sule Leoer arm (m) Torque (N-m) di- 0.397 For 39.7 dz= 0.1ga tor= 39.8 0.17. 10.199x200 ro 109 Data and Calculations Table 2 sidi hin DAO Mass Difference Position Leer arm (m) X 10.0 cm=0.100 m | di = 0.397 x2 = 75.0 cm=0.750 m dâ‚‚ =*). 253 *3=27.9 cm = 0.27mdp = 0).218 m = 100 g=0.100 kg 172 = 200 g =0.200 kg 1983 = 50 g = 0.050 kg Torque (N-m) 39.7 150.6 10.9 01. To LDDISO.6.-30.6.1 2 -0.218 m m % Error Data and Calculations Table 3 Support Position X Mass Position Lever arm (m) IN = 200 g 0.200 kg X'; = 10.0 cm=0.100 m | di = 0 128 m, =9498=0.9998 * = 49.1cm=0.90 m d = 0.269 (m.) exp kg 0.uas 0.11. in whole or in part
LABORATORY REPORT Meter Stick Data Table mass of inter 94.9 8= 0.0949 kg center balance m = 49.7 cm 0.497 m balang in molt inu % Difference Data and Calculations Table 1 Mass Position my=100 g 0.100 kg x = 10.0 cm -0.100 m m2 = 200 g =0.200 kg x2 =-11cm=0.69m opposte sule Leoer arm (m) Torque (N-m) di- 0.397 For 39.7 dz= 0.1ga tor= 39.8 0.17. 10.199x200 ro 109 Data and Calculations Table 2 sidi hin DAO Mass Difference Position Leer arm (m) X 10.0 cm=0.100 m | di = 0.397 x2 = 75.0 cm=0.750 m dâ‚‚ =*). 253 *3=27.9 cm = 0.27mdp = 0).218 m = 100 g=0.100 kg 172 = 200 g =0.200 kg 1983 = 50 g = 0.050 kg Torque (N-m) 39.7 150.6 10.9 01. To LDDISO.6.-30.6.1 2 -0.218 m m % Error Data and Calculations Table 3 Support Position X Mass Position Lever arm (m) IN = 200 g 0.200 kg X'; = 10.0 cm=0.100 m | di = 0 128 m, =9498=0.9998 * = 49.1cm=0.90 m d = 0.269 (m.) exp kg 0.uas 0.11. in whole or in part