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Consider the network of resistors shown in the figure below; notice that the battery has internal resistance of 2.00 ohms. R1 (7.00 22) M R2 (4.002) M $ (6.00 V) R3 (4.00 ) R4 (8.00 22) r (2.000) June 18. The current in the battery is equal to A. 2.00 mA. B. 0.250 mA. C. 0.500 A. D. 0.250 A E. 2.00 A 19. The potential difference across the terminals of the battery from point a to point bis equal to A. 6.00 v. B. 4.00 v. C. 5.50 v. D. 4.80 V. E. 5.00 V. 20. The current in the 8.00 ohm resistor is equal to A. 0.750 mA B. 0.125 A C. 0.625 mA. D. 0.750 A. E. 0.625 A.
In the circuit below, the ammeter has an internal resistance of 200.0 ohms. The voltmeter has a sensitivity of 50.00k per Volt and is being used on the 10 Volt scale. The battery is an "ideal battery", having negligible internal resistance and an unknown EMF. The voltmeter reads 4.286 Volts, and the ammeter reads 0.03000 mA. R1 (156.943 ka) ६ Rx 21. The current in the unknown resistance Requals A. 0.0300 mA B. 0.008571 mA. C. 0.02143 m. D. 0.02413 m. E. 0.008571 A. 22. The unknown resistance RX is equal to A. 500.00 Β. 500.0 ΚΩ. C. 150.0 ko. D. 200.00 E. 200.0 kn