Answer Happy

Slope of the H2O melting line. (a) Use the Clausius-Clayperon equation to compute the slope dp/dT of the ice-to-water melting line near room pressure, in SI units (Pa/K). (b) The triple point of water is at T = 273.16 K, p = 612 Pa. The freezing point of water at atmospheric pressure is at T = 273.15 K. Is the slope you computed in part (a) consistent with these numbers, to within their stated precision? Here are some data on H2O: • The molecular weight is 1 +1 + 16 which means that a mole of water has a mass of 18.0 g. • The density of liquid water near the freezing line at atmospheric pressure and below is 1.00 g/cm3 • The density of ice on the melting line is 8.3% less than the density of liquid water. • The latent heat of fusion for the ice-to-liquid water transition is 3.33 x 105 J/kg.