[b] For Example 22.6 (Calculating Current that produces a Magnetic Field) in Section 22.9 (Ampere's Law) of the textbook

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B For Example 22 6 Calculating Current That Produces A Magnetic Field In Section 22 9 Ampere S Law Of The Textbook 1 (13.76 KiB) Viewed 30 times

B For Example 22 6 Calculating Current That Produces A Magnetic Field In Section 22 9 Ampere S Law Of The Textbook 2 (13.76 KiB) Viewed 30 times

B For Example 22 6 Calculating Current That Produces A Magnetic Field In Section 22 9 Ampere S Law Of The Textbook 3 (26.05 KiB) Viewed 30 times

For Example 22.6 (Calculating Current that produces a Magnetic Field) in Section 22.9 (Ampere's Law) of the textbook, replace the phrase "twice the strength" with “Y times the strength and the distance from the wire with X cm and then solve the example. Show your work.
EXAMPLE 22.6 Calculating Current that produces a Magnetic Field Find the current in a long straight wire that would produce a magnetic field twice the strength of the Earth's at a distance of 5.0 cm from the wire. M/ 27 can Strategy The Earth's field is about 5.0 x 10-5 T, and so here B due to the wire is taken to be 1.0 x 10-4 T. The equation B = be used to find 1, since all other quantities are known. Solution Solving for I and entering known values gives 2008 2(5.0x10m) (10x104) 1 4x10 mA 2.2.25 Pa = 25 A