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3:46 Expert Q&A Done Internet HER For Problems 10-18, Refer to Problem 3 of Test 1 Handout: Given: 45 mph (+ x-directi

Posted: Fri Apr 29, 2022 11:28 am
by answerhappygod
3 46 Expert Q A Done Internet Her For Problems 10 18 Refer To Problem 3 Of Test 1 Handout Given 45 Mph X Directi 1
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3 46 Expert Q A Done Internet Her For Problems 10 18 Refer To Problem 3 Of Test 1 Handout Given 45 Mph X Directi 2
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3 46 Expert Q A Done Internet Her For Problems 10 18 Refer To Problem 3 Of Test 1 Handout Given 45 Mph X Directi 3
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3 46 Expert Q A Done Internet Her For Problems 10 18 Refer To Problem 3 Of Test 1 Handout Given 45 Mph X Directi 4
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3:46 Expert Q&A Done Internet HER
For Problems 10-18, Refer to Problem 3 of Test 1 Handout: Given: 45 mph (+ x-direction towards right; -x-direction towards left) a == -32.2 ft/s? (+ y-direction = upward: -y-direction = downward) sy -30 ft
MCH 202 NAME: Test #1 3.) While in "Hot Pursuit" of those Duke Boys, Roscoe makes a wrong turn onto an out-of-service bridge! If his initial velocity straight off the end of the 30' high bridge is 45 mph: a.) How far from the end of the bridge will his squad car land in the muddy swamp? b.) What will his velocity, V, be upon impact and at what angle, 0, with respect to surface of the swamp will the squad car stick in the mud Note: Acceleration of Roscoe's squad car during flight is 32.2t4s" (downward) and air resistance is negligible in Hazzard County! 30' --VAM Sx
(2 points) 15. Write the letter for the answer that best completes the following statements. In order to determine the vertical component of final velocity, in the muddy swamp. The best constant acceleration equation from the text to use is : a. Equation 1 (y-direction) b. Equation 1 (x-direction) c. Equation 11 (y-direction) d. Equation 11 (x-direction) (4 points) 16. The vertical component of final velocity (Vxy) in the muddy swamp is: a. -44.11 ft/s -21.9 ft/s -66.01 ft's -15.78 ft/s b. C. d. (2 points) 17. a. The final velocity V, in the muddy swamp is: 93.35 ft/s b. 79.38 fts 53.74 ft/s d. 72.8 ft/s . Oo (2 points) 18 The angle 9 for V2 is: a. 56.24 Degrees in Q2 b. 56.24 Degrees in 04 33.76 Degrees in Q2 d. 33.76 Degrees in Q4 C. Q2 Q1 Ref. for Prob. 18 3 9 59 V Q4 V₂ Q3