(b) a A copper rod has a length of 1m and a uniform cross-sectional area of 5 marks 3cm². The specific heat capacity of

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

(b) a A copper rod has a length of 1m and a uniform cross-sectional area of 5 marks 3cm². The specific heat capacity of

Post by answerhappygod »

B A A Copper Rod Has A Length Of 1m And A Uniform Cross Sectional Area Of 5 Marks 3cm The Specific Heat Capacity Of 1
B A A Copper Rod Has A Length Of 1m And A Uniform Cross Sectional Area Of 5 Marks 3cm The Specific Heat Capacity Of 1 (54.2 KiB) Viewed 27 times
(b) a A copper rod has a length of 1m and a uniform cross-sectional area of 5 marks 3cm². The specific heat capacity of copper at constant pressure can be taken to be independent of temperature (for simplicity) and have the value 400 Jkg‘’K. The density of copper is 8933 kgm. Find the heat capacity of the rod.
(c) One end of the rod described in (b) is heated to temperature T, and the 8 marks other to temperature T, by putting them in contact with large heat reservoirs at those temperatures (T. ZT). After a time, a steady heat flow is set up along the bar and the temperature gradient is constant along the rod. Show that the temperature a distance x from the colder end of the rod is given by T(x) =T, +2, -1.. L The rod is now isolated from the two reservoirs and held at constant pressure. It is thermally insulated so that no net heat leaves the rod, and it comes to a uniform final temperature Tp. Show that this implies: f(T(*) -Ty )dx=0 Hence show that the final uniform temperature of the rod is given by T TH +T. 2 . Equation 1.1
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply