B er | 1 1 TO Each end of a long slender bar of mass mand length is attached to a small roller of negligible mass and
Posted: Fri Apr 29, 2022 10:32 am
B er | 1 1 TO
Each end of a long slender bar of mass mand length is attached to a small roller of negligible mass and friction such that, when released, the bar will roll down the circular half-pipe surface in a clockwise sense. The normal forces between the rollers at A and B and the half-pipe surface are denoted as NA and NB. respectively. The acceleration of the bar's centre of mass along the normal- tangential directions shown (i.e., en and ē
are denoted as a and a respectively, and its angular acceleration is a. Which is the correct sum of moments on the bar taken about point A as it is released from rest from the configuration shown? n IMPORTANT: Terms that may be identified as being equal to zero MUST NOT appear in the equation (this could include quantities that are defined in the problem statement).
V2 2 mgt - V2NB = 1 ml?a - mtan 12 - V2 4 1 V mge - V2 Nne = 3 mea = 1 e-2 12 me²a+ mear V2 4 mgt - V2 -NB! ! = 2 = 6 12 mgl - 4 -Nße: 1 α + 12 V2 Not = 1; mtºa+] mea, - mean mge – v2Nt = ia mea V2 2 1 = 12 O 12 mgt 4 1 V2 Npl = 2 -me a mean 1 = - 12 2.
Each end of a long slender bar of mass mand length is attached to a small roller of negligible mass and friction such that, when released, the bar will roll down the circular half-pipe surface in a clockwise sense. The normal forces between the rollers at A and B and the half-pipe surface are denoted as NA and NB. respectively. The acceleration of the bar's centre of mass along the normal- tangential directions shown (i.e., en and ē
V2 2 mgt - V2NB = 1 ml?a - mtan 12 - V2 4 1 V mge - V2 Nne = 3 mea = 1 e-2 12 me²a+ mear V2 4 mgt - V2 -NB! ! = 2 = 6 12 mgl - 4 -Nße: 1 α + 12 V2 Not = 1; mtºa+] mea, - mean mge – v2Nt = ia mea V2 2 1 = 12 O 12 mgt 4 1 V2 Npl = 2 -me a mean 1 = - 12 2.