Answer Happy

V20 21 Reservoir Go Pump Piping System Problem (50% Written, 50% Oral) Suppose the pump of Fig. P14–24 has a performance that follows a parabolic curve fit, Havailable = Ho - aj ?, where Ho = 19.8 m is the pump's shutoff head, and a = 0.00426 m/(Lpm)2 is a coefficient of the curve fit. The pipe, both upstream and downstream of the pump, has an inner diameter of 2.0 cm and nearly zero roughness. The minor loss coefficient associated with the sharp inlet is 0.50, each valve has a minor loss coefficient of 2.4, and each of the three elbows has a minor loss coefficient of 0.90. The contraction at the exit reduces the diameter by a factor of 0.60 (60% of the pipe diameter), and the minor loss coefficient of the contraction is 0.15. Note that this minor loss coefficient is based on the average exit velocity, not the average velocity through the pipe itself. The total length of pipe is 8.75 m, and the elevation difference is (z1 – 22) = 4.6 m. Estimate the volume flow rate through this piping system using the Colebrook Equation and Excel Solver or What-If applications. Repeat using the Haaland Equation. How would the solution procedure be changed if you had a Power law fluid? Would a Power law fluid have a higher or lower flow rate than a Newtonian fluid? 22- FIGURE P14-24 Repeat the above problem, but instead of a smooth pipe, let the pipe roughness be 0.12 mm. Estimate the volume flow rate through this piping system using the Colebrook Equation and Excel Solver or What-If applications. Colebrook Equation: * =-2log {smooth pipe} Haaland Equation: -1.8log[Re, & /p] 2.51 =- k + 3.7D Reli =