Each end of a long slender bar of mass mand length is attached to a small roller of negligible mass and friction such th

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answerhappygod
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Each end of a long slender bar of mass mand length is attached to a small roller of negligible mass and friction such th

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Each End Of A Long Slender Bar Of Mass Mand Length Is Attached To A Small Roller Of Negligible Mass And Friction Such Th 1
Each End Of A Long Slender Bar Of Mass Mand Length Is Attached To A Small Roller Of Negligible Mass And Friction Such Th 1 (43.88 KiB) Viewed 31 times
Each End Of A Long Slender Bar Of Mass Mand Length Is Attached To A Small Roller Of Negligible Mass And Friction Such Th 2
Each End Of A Long Slender Bar Of Mass Mand Length Is Attached To A Small Roller Of Negligible Mass And Friction Such Th 2 (24.53 KiB) Viewed 31 times
Each End Of A Long Slender Bar Of Mass Mand Length Is Attached To A Small Roller Of Negligible Mass And Friction Such Th 3
Each End Of A Long Slender Bar Of Mass Mand Length Is Attached To A Small Roller Of Negligible Mass And Friction Such Th 3 (39.08 KiB) Viewed 31 times
Each end of a long slender bar of mass mand length is attached to a small roller of negligible mass and friction such that, when released, the bar will roll down the circular half-pipe surface in a clockwise sense. The normal forces between the rollers at A and B and the half-pipe surface are denoted as NA and NB, respectively. The acceleration of the bar's centre of mass along the normal- tangential directions shown (i.e., en and ē :) are denoted as a and a t' respectively, and its angular acceleration is a. Which is the correct sum of moments on the bar taken about point A as it is released from rest from the configuration shown? n IMPORTANT: Terms that may be identified as being equal to zero MUST NOT appear in the equation (this could include quantities that are defined in the problem statement).

B ē, !! 1 1 1 m

V2 2 mgt - V2NB 12 me a- mean ?- V2 4 1 V2 2 -me²a ya mge – = ENpl = 1 / me a BE +- ? Noe = izmea+ mla V2 1 4 mgt - = 2 1 2 12 4 mgl - 4 1 NBC 1 12 V2 Not = 1; mi-a+] mea, - mean mge – v2V,t = ia mea 12 2 1 = 12 O V2 mgt- 4 12 1 NB! = 2 12 m-a - mean 1 me²a- 2.
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