A solid aluminum alloy [E = 69 GPa; a = 23.6 x 10-6/C] rod (1) is attached rigidly to a solid brass [E = 115 GPa; a = 18

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A solid aluminum alloy [E = 69 GPa; a = 23.6 x 10-6/C] rod (1) is attached rigidly to a solid brass [E = 115 GPa; a = 18

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A Solid Aluminum Alloy E 69 Gpa A 23 6 X 10 6 C Rod 1 Is Attached Rigidly To A Solid Brass E 115 Gpa A 18 1
A Solid Aluminum Alloy E 69 Gpa A 23 6 X 10 6 C Rod 1 Is Attached Rigidly To A Solid Brass E 115 Gpa A 18 1 (53.23 KiB) Viewed 25 times
A solid aluminum alloy [E = 69 GPa; a = 23.6 x 10-6/C] rod (1) is attached rigidly to a solid brass [E = 115 GPa; a = 18.7 x 10-6/C] rod (2), as shown in the figure. The compound rod is subjected to a tensile load of P = 4.9 kN. The diameter of each rod is 8 mm. The rods lengths are L = 475 mm and L2 = 675 mm. Compute the change in temperature required to produce zero horizontal deflection at end of the compound rod. L L2 (1) B Р (2) с Part 1 What are the internal forces F, and F2 in rods (1) and (2), respectively? Use the sign convention for internal axial forces discussed in Section 5.3. F = i KN z F2 = i KN

Part 2 Determine the cross-sectional area for the rods. A= i mm Save for Later Attempts: unlimited Submit Answer Part 3 If there were no temperature change, what would be the elongations 81.p and 82.p of rods (1) and (2), respectively, due to the load P? 01.p = mm 82.p = i mm

Part 4 If there were no temperature change, what would be the magnitude of the horizontal deflection at end of the compound rod due to load P? UCP = i mm e Textbook and Media Save for Later Attempts: unlimited Submit Answer Part 5 Compute the change in temperature required to produce zero horizontal deflection at end of the compound rod. Enter a positive value for a temperature increase, or a negative value for a temperature decrease. AT = i °C
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