theta 2 = 100 L2 = 110 mr1 = 3.60 mr2 = 3.48 mr3 = 3.24 mr4= 2.88

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answerhappygod
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theta 2 = 100 L2 = 110 mr1 = 3.60 mr2 = 3.48 mr3 = 3.24 mr4= 2.88

Post by answerhappygod »

theta 2 = 100
L2 = 110
mr1 = 3.60
mr2 = 3.48
mr3 = 3.24
mr4= 2.88
Theta 2 100 L2 110 Mr1 3 60 Mr2 3 48 Mr3 3 24 Mr4 2 88 1
Theta 2 100 L2 110 Mr1 3 60 Mr2 3 48 Mr3 3 24 Mr4 2 88 1 (66.73 KiB) Viewed 17 times
Theta 2 100 L2 110 Mr1 3 60 Mr2 3 48 Mr3 3 24 Mr4 2 88 2
Theta 2 100 L2 110 Mr1 3 60 Mr2 3 48 Mr3 3 24 Mr4 2 88 2 (66.73 KiB) Viewed 17 times
You need to find unknown locations L and Land angular positions of the third and fourth blocks e, and e, by solving the balancing equations: 3a =Ž (mr),20,=0 347 = ÈL (mr),20, = 0 i=1 12 These equations should be solved in Real form for unknowns 0, 0, 2, and L. (highlighted in red), i.e. you need to solve 4 equations with 4 unknowns (for example using numerical solution of a system in equation function in Matlab): (mr), cos(@)+(mr), cos(()+(mr), cos(C)+(mr), cos(@))=0 (mr), sin(0)+(mr), sin(0)+(mr), sin(0)+(mr), sin(0.) = 0 (mr), cos(@4, +(mr), cos(@) +(mr), cos(@p), = 0 [(mr), sin(0,)4, +(mr), sin(@)2 + (mr), sin(0)4 = 0 Alternatively using first two equations, you can determine , and e (hint: cos' 0+ sin 0=1). Then from the last two equations you can find L, and 2
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