Answer Happy

Question 4 For the first part of this question, we will consider Calum and his cat on a trip to the river. At the moment shown in Figure Q4-1, Calum is pushing the canoe into the river with a constant speed of Vpush = 2 m/s. The river is 50 meters wide and with a water speed equal to 5 m/s. (a) Calculate the distance (AB) and time (tab) needed for the canoe to cross the river. [10] Width River = : 50 m VPush = 2 m/s X B Speedwater = 5 m/s Figure Q4-1

For the second part of the question, we will consider the situation presented in Figure Q4-2. The cat has now reached the right bank of the river but wishes to go back to the left side. Unfortunately, the cat is now only 100 meters away from a wee waterfall and does not wish to be wet. Note: the speed of the water flowing in the river is still 5 m/s. (b) If the cat can row at 4 m/s in still water (Vrowing), will he be able to reach the left riverbank with- out touching the wee waterfall? If yes, calculate the minimum time he takes to reach the left bank. [10] Width River = 50 m Ľ. Х Speedwater = 5 m/s = Distance waterfall 100 m == Waterfall Figure Q4-2