ALSO find the 3-dB frequency, fH. a.15 KHz b.2 GHz c.315 MHz d.212 MHz
Posted: Fri Apr 29, 2022 9:14 am
ALSO find the 3-dB frequency, fH.
a.15 KHz
b.2 GHz
c.315 MHz
d.212 MHz
It is required to analyze the frequency response of the IC current source-loaded CS amplifier for the case Rsig = 0. Here, IBIAS = 100 PA, (W/L)2 = 2(W/L)3, Cgs1 = 50 fF, Cgd1 = 10 fF, Cdb1 = Cdb2 = 20 fF, Cgd2 = 10 fF, unCox = 500 A/V^2, (W/L)1 = 20, and VA1 = |VA2| = 6 V. For simplicity, assume that the signal voltage at the gate of Q2 is zero. Find the low- frequency (dc) gain VO/Vsig. Hint: The total capacitance at the output node = Cdb1 +Cdb2 +Cgd2, and the equivalent circuit is as shown. Note that we are not neglecting output capacitances and that Rsig =0. Q3 Q2 Ced1 HE + Ibias ( OV. w Vsig Cgsi = Vgsl 8mi Vgs < rol 7.2 Cabl + Cdb2= • Cad2 V Rsig = = = IH = = Q1 RL CL V sig оа. -90 V/V Ob -30 V/V ос. -65 VN Od -20 VNV
a.15 KHz
b.2 GHz
c.315 MHz
d.212 MHz
It is required to analyze the frequency response of the IC current source-loaded CS amplifier for the case Rsig = 0. Here, IBIAS = 100 PA, (W/L)2 = 2(W/L)3, Cgs1 = 50 fF, Cgd1 = 10 fF, Cdb1 = Cdb2 = 20 fF, Cgd2 = 10 fF, unCox = 500 A/V^2, (W/L)1 = 20, and VA1 = |VA2| = 6 V. For simplicity, assume that the signal voltage at the gate of Q2 is zero. Find the low- frequency (dc) gain VO/Vsig. Hint: The total capacitance at the output node = Cdb1 +Cdb2 +Cgd2, and the equivalent circuit is as shown. Note that we are not neglecting output capacitances and that Rsig =0. Q3 Q2 Ced1 HE + Ibias ( OV. w Vsig Cgsi = Vgsl 8mi Vgs < rol 7.2 Cabl + Cdb2= • Cad2 V Rsig = = = IH = = Q1 RL CL V sig оа. -90 V/V Ob -30 V/V ос. -65 VN Od -20 VNV