Pspice question/BJT There is some solutions on answers but all of them are incorrect.If you copy paste it i will give thum

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answerhappygod
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Pspice question/BJT There is some solutions on answers but all of them are incorrect.If you copy paste it i will give thum

Post by answerhappygod »

Pspice question/BJT
There is some solutions on answers but all of them are incorrect.If you copy paste it i will give thumbs down
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Pspice Question Bjt There Is Some Solutions On Chegg But All Of Them Are Incorrect If You Copy Paste It I Will Give Thum 1
Pspice Question Bjt There Is Some Solutions On Chegg But All Of Them Are Incorrect If You Copy Paste It I Will Give Thum 1 (141.9 KiB) Viewed 22 times
Pspice Question Bjt There Is Some Solutions On Chegg But All Of Them Are Incorrect If You Copy Paste It I Will Give Thum 2
Pspice Question Bjt There Is Some Solutions On Chegg But All Of Them Are Incorrect If You Copy Paste It I Will Give Thum 2 (8.14 KiB) Viewed 22 times
2.2. In the following circuit calculate R1, R2, RC and RE to achieve gain of 10. Note the followings: . The supply voltage is 5V. Choose collector current around 1mA. Choose R1 and R2 such that the design is independent of Beta. Choose RE such that the design is not prone to VBE variations. Choose RC to get gain of 10. . R1 RC C1 th Q1 QbreakN V1 5Vdc V2 R2 RE VOFF = 0 VAMPL = 10mV FREQ = 1000 AC = w W 0 Cir 2.2 2.3. Simulate the above circuit using SPICE to verify your calculations. Note the followings: Use NPN model that you used in the previous lab. The frequency of interest is 1 KHz. 1 1/3 . . Choose C1 such that it does not affect the AC output but it is not too large, either. Start with 10 micro-farad capacitor and reduce it until it starts affecting AC amplitude then decide on the value of C1. Gain: Apply a 10mV peak sine-wave to the input, check the output waveform using transient analysis. By dividing the output amplitude to the input amplitude find the gain. Input impedance: Add a series resistor to the input source. Apply 10mV peak sine-wave and check the output amplitude. Increase the value of the series resistor until the output amplitude drops by half. At this point, the value of the resistor indicates the input impedance. Output impedance: Add a resistor at the output as load. (Remove the input resistor). Reduce the value of the load resistor. The value of the load resistor when the output amplitude drops by half is equal to the output resistance. (NOTE THAT YOU CANNOT ADD THE LOAD RESISTOR directly to the output node without disturbing the DC bias point. You need to DC decouple the load resistor from the collector node. Therefore you need to add a decoupling capacitor between the load resistor and the output node. Use the same value of C1 that you optimized in the previous part.)
Cir 2.1 Use the following model parameters for the BJT: .model Obreakn NPN IS-le-16 BF=100 VAF=5
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